-0.5x^2+36x-166=0

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Solution for -0.5x^2+36x-166=0 equation:



-0.5x^2+36x-166=0
a = -0.5; b = 36; c = -166;
Δ = b2-4ac
Δ = 362-4·(-0.5)·(-166)
Δ = 964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{964}=\sqrt{4*241}=\sqrt{4}*\sqrt{241}=2\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{241}}{2*-0.5}=\frac{-36-2\sqrt{241}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{241}}{2*-0.5}=\frac{-36+2\sqrt{241}}{-1} $

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